### Here is Mr. H's Percent Problem

The problem I found is this

A 800 seat multiplex is divided into 3 theatres. There are 270 seats in Theatre 1, and there are 150 more seats in Theatre 2 than in Theatre 3. How many seats are in Theatre 2?

Please post an answer by placing it in my comments.

Did you get the right answer?

The solution can be found here

A great tutorial on how to solve percent problems.percent questions.

Good luck

Mr. H

## 2 Comments:

There are

340seats in theatre 2. Here ismysolution :800 seats are divided into 3 theatres.

270seats are in theatre 1,340seats are in theatre 2 and190seats are in theatre 3.800 - 270 = 530

530 - 150 = 380

380 divided by 2 = 190

190 =

theatre 3190 + 150 = 340

340 =

theatre 2I hope it's correctly done. (:

y is Theatre 3.

I went 270+(150+y)+y =800

-270+150=420

Now it is 420+2y=800 because there are 2 'y's in the equation I just put them together.

I subtracted 420 from 800

-(800-420=280)

Since there are 2 'y's I divided that answer by 2.

-280/2=190 meaning Theatre 3 has 190 seats.

Add 150 more to 190 because Theatre 2 has 150 more seats than Theatre 3.

-190+150=340

Theatre 1 has 270 seats

Theatre 2 has 340

Theatre 3 has 190

Altogether = 800

I think this is right*

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