Monday, January 16, 2006

Here is Mr. H's Percent Problem

The problem I found is this

A 800 seat multiplex is divided into 3 theatres. There are 270 seats in Theatre 1, and there are 150 more seats in Theatre 2 than in Theatre 3. How many seats are in Theatre 2?


Please post an answer by placing it in my comments.

Did you get the right answer?

The solution can be found here



A great tutorial on how to solve percent problems.percent questions.

Good luck

Mr. H




Français/French Deutsch/German Italiano/Italian Português/Portuguese Español/Spanish 日本語/Japanese 한국어/Korean 中文(简体)/Chinese Simplified Tagalog/Filipino

2 Comments:

At 6:09 PM, Blogger Racquel816 said...

There are 340 seats in theatre 2. Here is my solution :

800 seats are divided into 3 theatres. 270 seats are in theatre 1, 340 seats are in theatre 2 and 190 seats are in theatre 3.


800 - 270 = 530
530 - 150 = 380
380 divided by 2 = 190
190 = theatre 3
190 + 150 = 340
340 = theatre 2

I hope it's correctly done. (:

 
At 6:13 PM, Blogger .dhona8-16 said...

y is Theatre 3.

I went 270+(150+y)+y =800
-270+150=420

Now it is 420+2y=800 because there are 2 'y's in the equation I just put them together.

I subtracted 420 from 800
-(800-420=280)
Since there are 2 'y's I divided that answer by 2.
-280/2=190 meaning Theatre 3 has 190 seats.

Add 150 more to 190 because Theatre 2 has 150 more seats than Theatre 3.
-190+150=340

Theatre 1 has 270 seats
Theatre 2 has 340
Theatre 3 has 190
Altogether = 800

I think this is right*

 

Post a Comment

<< Home